SQL: query goed uitgevoerd, maar hoe kan ik de inhoud zien van mijn query?? (Opgelost)

<?php
include('config.php');

$query = "SELECT DISTINCT userID FROM alive";
$resultID = mysql_query($query, $connect) or die("Data not found.");  

$goodresults = array();

for($x =  0 ;  $x <  mysql_num_rows($resultID) ; $x++)
	{
		$row = mysql_fetch_assoc($resultID);
		$qry = "select * from alive where userID = " . $row['userID'] . " ORDER BY aliveID LIMIT 1";
		$preResult = mysql_query($qry, $connect) or die("Data not found.");
		echo $preResult;
	}
?>

<?php
include('config.php');
 
$query = "SELECT DISTINCT userID FROM alive";
$resultID = mysql_query($query, $connect) or die("Data not found.");  
 
$goodresults = array();
 
for($x =  0 ;  $x <  mysql_num_rows($resultID) ; $x++)
	{
		$row = mysql_fetch_assoc($resultID);
		$qry = "select * from alive where userID = " . $row['userID'] . " ORDER BY aliveID LIMIT 1";
		$preResult = mysql_query($qry, $connect) or die("Data not found.");
		echo $preResult;
	}
?>