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 überleet
 |  | Citaat: //Contents for menu 1var menu1=new Array()
 menu1[0]='<a href="index.html">Main Page</a>'
 menu1[1]='<a href="athletics.html">Athletics Home</a>'
 
 //Contents for menu 2
 var menu2=new Array()
 menu2[0]='<a href="Sports/football/main.html">Football</a>'
 menu2[1]='<a href="#">Soccer</a>'
 menu2[3]='<a href="Sports/crosscountry/main.html">Cross-Country</a>'
 
 
 //Contents for menu 3
 var menu3=new Array()
 menu3[0]='<a href="Sports/boysbasketball/main.html">Basketball</a>'
 menu3[1]='<a href="#">Wrestling</a>'
 menu3[2]='<a href="Sports/swimming/main.html">Swimming</a>'
 dit wil ik bekomen en dus probeerde ik volgende functie uit om te testen (dus nog geen waarde, maar zelfs daar loopt het vast)
 
 
 Citaat: $array[1] = 'blaat';$array[2] = 'blaat';
 $array[3] = 'blaat';
 
 $i=1;
 $javascript = '<script>';
 while($array[$i] != null){
 $javascript .=	'var menu' .$i . '=new Array()
 menu1[0]='<a href="index.html">Main Page</a>'
 menu1[1]='<a href="index.html">Main Page2</a>'
 ';
 $i++;
 }
 
 $javascript .= '</script>';
 
 echo $javascript;
 
 ?>
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